The current age difference between two persons is 25. 9 years before the elder one's age was 6 times that of the younger one. What is sum of their current ages?

• 39-14=25 diff
  Soo 39+14=53
• 6 years agoHelpfull: Yes(12) No(5)
• let the ages are x,y;
  x-y=25------->(1)
  x-9=6*(y-9)------->(2)
  x-9=6y-54
  => x-6y=-45---->(3)
  from eqns 1 and 3
  x=39 and y=14
• 6 years agoHelpfull: Yes(10) No(0)
• LET YOUNGER=X AND ELDER =X+25;
  A/q, (X+25)-9=6(X-9)
  Solving the eqaution x=14 whicjh is theage of younger
  elder=25+14=39
  
  Diff is 25 and elder age is 6times age of younger .
• 6 years agoHelpfull: Yes(4) No(1)
• f-s=25,
  f-9=6(s-9),
  on solving f=39 and s=14
• 6 years agoHelpfull: Yes(2) No(0)
• Let current ages be x,x+25
  9 years ago x+25-9=6(x-9)
  X=14
  Youngerone age is 14
  Older one age is 39
• 6 years agoHelpfull: Yes(2) No(0)
• let us assume the current age of elder one is A
  given the current age difference is 25 so,the present age of younger is A-25
  before 9 years elders age=A-9
  9 years before younger age=A-25-9=A-34
  A-9=6A-204
  A=39
  the sum their current ages=39+39-25=53
• 6 years agoHelpfull: Yes(1) No(1)
• let two persons be x and y
  x is elder and y is younger
  so x-y=25 (difference of age between two people will be same throughout)
  9 years before x=6y
  hence 6y-y=25
  5y=25
  y=5
  x-y=25
  x=25+5=30
  therefore 9 years before age of x and y is 30 and 5
  current age of x=9+30=39
  current age of y=9+5=14
  sum of current age is 39+14=53
• 6 years agoHelpfull: Yes(1) No(0)
• x-y=25-----eq1
  x-9=6(y-9)
  x-6y=-45-----eq2
  solving eq1 and eq2,we get
  y=14 and x=39
• 6 years agoHelpfull: Yes(1) No(0)
• X-Y = 25 - - - - 1eqn
  (x-9)=6(y-9) - - - - 2eqn
  On solving eqn1 and eqn2
  X=39 and y=14
  X+Y =53
• 6 years agoHelpfull: Yes(1) No(1)
• Let x and y be two persons. Let x be elder one and y be younger one.
  Current age diff = x-y = 25--- 1
  (x-9)=6(y-9)
  x-9 = 6y-54
  6y-x=45 ---2
  solving 1 and 2 we get,
  y=14
  subs y=14 in 1
  x= 39
  therefore, sum = x+y= 14+39 = 53
• 6 years agoHelpfull: Yes(1) No(0)
• BEFORE 6 YEARS ELDER ONE'S AGE: 30
  YOUNGER ONE AGE: 5
  CURRENT AGE: 36 & 11 SO DIFFERENCE IS 25..... AND SUM IS 47.... 47 IS ANSWER....
• 6 years agoHelpfull: Yes(0) No(9)
• given, x-y=25,
  (x-9) = 6(y-9),
  FROM SOLVING ABOVE EQUATIONS we get,
  y = 13, x = 38.
  sum x+y = 51
• 6 years agoHelpfull: Yes(0) No(5)
• a-b=25
  a-9=6*(b-9)
  b+25-9=6*(b-9)
  5b=25
  b=5, a=30
• 6 years agoHelpfull: Yes(0) No(5)
• let x=Elder son's age and y- younger son's age
  so equation will be
  x - y = 23 ---------(i)
  and before 9 yrs
  x - 9 = 6 ( y - 9 ) -------(ii)
  after solving both the equations,
  y = 14 and
  X = 39 .
• 6 years agoHelpfull: Yes(0) No(0)
• x-y=25
  x-9=6(y-9)
  x=y+25
  x-9=6(y-9)=>y+25-9=6y-54=>5y=70=>y=12
  x=y+25=>x=12+25=37
  x+y=49
• 6 years agoHelpfull: Yes(0) No(1)
• 36.26
  one age is 5.18
  other age is 36.26
• 5 years agoHelpfull: Yes(0) No(1)
• x-y =25--------------1
  x=6y
  9 year's before=> x-9 =6(y-9)
  X-6y = -45---------------2
  By solving 1and 2
  X=39
  Y=14
  sum of x and y is 53
• 5 years agoHelpfull: Yes(0) No(0)
• x-y=25
  x-9=6(y-9)
  on solving the above two equation we obtain the value as
  x=39 &y=14
  x+y=39+14=53
• 5 years agoHelpfull: Yes(0) No(0)
• x-y=5
  x-9=6(y-9)
  x=14,y=39
  x+y=53
• 5 years agoHelpfull: Yes(0) No(0)
• x=6y
  x=5(assume)
  5=30
• 5 years agoHelpfull: Yes(0) No(0)
• let the elder one be x
  x-y=25------------------ 1
  9 years before elder's age was 6 times that of younger one
  (x-9)=6(y-9)
  x-6y=-45-----------------2
  solving two equations we get
  x=39,y=14
  x+y=53
• 5 years agoHelpfull: Yes(0) No(0)