A boy move 6 m in west then he turn towards south and move 20 m then turn towards east and move 12 
m again move toward north and move 12 m . How much dist he is away from his starting point

• So simple ......
  let us take a new approach to solve this problem..Given data
  
  W S E N
  6 20 12 12.
  ...Note:-Remember the opposite poles should be subtracted and like poles should be added.
  Then E-W=6 (where E>W and keep the value in higher pole only), similarly .....S-N=8.....
  so if we left with adjacent poles the take the logic as ........sqrt(a^2+b^2)
  in our prbm we have sqrt(6^2+8^2)......sqrt(100)......That is Ans 10(towards south ,because S>E).....
  Thank you.............
• 7 years agoHelpfull: Yes(5) No(0)
• 10m south east
• 7 years agoHelpfull: Yes(1) No(0)
• 10m south east
• 7 years agoHelpfull: Yes(1) No(0)
• 14m away from starting point and in SE direction
• 7 years agoHelpfull: Yes(1) No(4)
• He is 14m away from the starting point and currently, he is standing in South-East Direction.
• 7 years agoHelpfull: Yes(1) No(4)
• 10m (South-East)
• 7 years agoHelpfull: Yes(1) No(0)
• √(8^2+6^2)=10
• 6 years agoHelpfull: Yes(1) No(0)
• 10m (south-east)
• 7 years agoHelpfull: Yes(0) No(0)
• ___6m____(A)
  |
  |
  | (B) calculate the distance between A to B 6^2+8^2=100. so sqrt(100). Ans =10m
  20m |
  | |12m
  |______12m_________|
• 7 years agoHelpfull: Yes(0) No(0)
• 10m south east
• 6 years agoHelpfull: Yes(0) No(0)
• total distance is away from starting point = sqrt of ((20-12)^2 + (12 -6)^2) = sqrt(8^2 + 6^2) = 10 m
• 6 years agoHelpfull: Yes(0) No(0)
• √(20^2+6^2)=√(436)=20.88
• 6 years agoHelpfull: Yes(0) No(0)