An empty bucket was filled with A type of water. When the bucket was half-empty, it was filled with B type of water. Again when the bucket was half-empty. It was filled with A type of water. When the bucket was half-empty again, it was filled with B type of water. What is the percentage of B type water at present in the bucket?

• values are in %
  A B
  1 100 0 {initialy only A}=100
  2 50 50 {B added A half}=100
  3 75 25 {A addes B half}=100
  4 37.5 62.5 {B added A half}=100
• 6 years agoHelpfull: Yes(11) No(1)
• ans: 65%
  1=> 100% A
  2=> HALF EMPTY 50% A
  3=> REMAINING 50% A, FILL 50% B
  4=> HALF EMPTY 25% A 25% B
  5=> FILL 50% A, REMAINING 25%B 25% A
  6=>HALF EMPTY >> A'S PERCENTAGE OF EMPTY SHOULD BE HIGH SINCE A IS 75%, 35% A, 15%B
  7=> FILL 50%B , REMAINING 35%A, 15%B
  SO PERCENTAGE OF B IS 65%
• 6 years agoHelpfull: Yes(3) No(9)
• ans: 62.5
• 6 years agoHelpfull: Yes(1) No(4)
• 3(n)=4(n-4)
  ->n=16
  volume of tank= 16*3=48
• 6 years agoHelpfull: Yes(0) No(2)
• 1 a=50
  2 b=25
  3 a=12.5
  4 b=6.25
  %of b =(6.25+25)*100/93.75=33.33
• 6 years agoHelpfull: Yes(0) No(1)
• the answer is 37.5%
  
  initialy A=100ltrs
  
  
  1st operation
  a=50ltrs b=50 ltrs
  
  2 nd operation
  
  a=50/2+50=75 b=50/2=25
  
  
  3rd operation
  
  a=75/2=37.5 b=25/2+50=62.5
  
  
  
  therefore a is 37.5%
• 5 years agoHelpfull: Yes(0) No(0)