Elitmus
Exam
Numerical Ability
Arithmetic
in an infinite geomatric progression,each term is equal to 2 times the sum of the terms that follow.if the first term of the series is 8,find the sum of the series.
a)12 b)32/3
c)34/3 d)No any
Read Solution (Total 3)
-
- ans is 12.
let 8=a/r,next term is a,next term ar and so on
as per ques
8=2(a+ar+ar2+ar3+...........infinity)
8=2*a/1-r
a/r=2*a/1-r
r=1/3
sum of infinite term of gp is
1st term/1-r= 12 - 7 years agoHelpfull: Yes(9) No(2)
- Let the terms are ... a, ar, ar2, ar3,............infinity.
as per ques,
a=2(ar+ar2+ar3+...........infinity),
=>a=2(a+ar+ar2+ar3+...........infinity - a),
=>a=2(a/1-r) - 2a..............................bcz S(infinity)=(a/1-r),
=>a=2a(r/1-r),
=>1=2(r/1-r),
=>r=1/3
Therefore, sum of infinite term of GP is = a/1-r
After putting value of a=8 and r=1/3,
we get sum of infinite term of GP is = 12. Ans. - 7 years agoHelpfull: Yes(6) No(0)
- For the geometric series, a+ar+ar2+... with |r|
- 7 years agoHelpfull: Yes(0) No(4)
Elitmus Other Question