In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers??(Need a simple approach to solve this)

1) 14
2) 7
3) 6
4) 5

• 5 ways
  
  3 numbers ... 199,200,201
  5 numbers .. 118,119,120,121,122
  15 numbers ...33,34,......39,40,41...47
  16 numbers ....30,31....37,38...45
  
  25 numbers .....12,13,.....23,24,25,....35,36
  
  simple approach is
  
  sum of two or more consecutive natural number = no of odd factros other than 1 ...
  
  600 = 2^3*3*5^2
  no of odd factros other than 1 = (1+1)*(2+1) -1 = 6-1 = 5
• 11 years agoHelpfull: Yes(2) No(0)