Predict the output of following code:
main()
{
int a=10,x=20;a=a++ + 10; // a = 10+10 first a is increment to 11 but
overwritten by 20
x=x++ + ++a; // x = 20 + 21 a is incremented first from 20 to 21
printf(“%d,%d”,a,x);
}
1. 22,43
2. 12,21
3. 10,20
4. 42,42

• 21,41 as first value will be incremented by 1 (from 10 to 11) then 10 is added to it that's why value of a will be 21.
  X=20+21 that's why value of x will be 41
• 6 years agoHelpfull: Yes(6) No(0)
• firstly a=10, x=20;
  a=a++(10) + 1= 20 , but a++,so a is postfix->a=20+1=21
  x=x++(20) + ++a(21+1)=42, so x is also here postfix->42+1=43
• 6 years agoHelpfull: Yes(1) No(0)
• 22,43 1st a++ +10=a=21,x=x++ + ++a=41,but there is post increment so after that a became 22 and k become 43
• 6 years agoHelpfull: Yes(1) No(0)
• a=10
  a=11+10=21
  x=20+22=42
  x increased 1 time so x=43
  So ans:a=22,x=43
• 6 years agoHelpfull: Yes(1) No(0)