Predict the output of following code:
main()
{
int i=10;
printf(“%d,%d”,++i,++i);
}
1. 11,12
2. 12,11
3. 10,11
4. 11,10

• the answer will be 12,12.
  As both are pre increment operators.
• 6 years agoHelpfull: Yes(17) No(6)
• The answer is 12,11 since the printf statement executes from right to left.
• 6 years agoHelpfull: Yes(11) No(7)
• ans is 12 12 because printf prints from right to left
  so it will first increase the value twice i.e from 1st ++i it will be 11 than for another ++i it will be 12 and than after this both %d will take this 12 as the value and will print
• 6 years agoHelpfull: Yes(8) No(1)
• The answer is 11,12.
• 6 years agoHelpfull: Yes(6) No(6)
• ++i is the prefix increment operation.
  initially i=10
  first , ++i = ++10 = 10+1 = 11
  second , ++i = ++11 = 11+1 = 12
  So, Output is : 11 , 12.
• 6 years agoHelpfull: Yes(6) No(8)
• Printf statement executes from the last so first it prints 11 then prints 12
  Ans:12 11
• 6 years agoHelpfull: Yes(3) No(2)
• 12,11 since printf print from right to left
• 6 years agoHelpfull: Yes(1) No(1)
• In the above program output should (11,12) because it follows pre_increment
• 6 years agoHelpfull: Yes(1) No(3)
• Printf frist print value of i and after increase ++i so answer
  I=10 after i=11 after increasei=12
  Answer is 10 and 11
• 6 years agoHelpfull: Yes(0) No(1)
• Here unary minus (or negation) operator is used twice. Same math rules applies, ie. minus * minus = plus.
  Note: However you cannot give like --2. Because -- operator can only be applied to variables as a decrement operator (eg., i--). 2 is a constant and not a variable.
• 6 years agoHelpfull: Yes(0) No(0)
• 11 ,12,first of aall ++i means increment i so int i will incremen two times because two ++i's are there
• 6 years agoHelpfull: Yes(0) No(0)