Predict the output of following code:
main()
{
if( printf(“”)) // prints content of printf statement and
//takes length of the string for if case
case its 1, So true
printf(“Face”);
else
printf(“Focus”);
}

1. Error
2. Face
3. “”Focus
4. Face

• There are two cases here:
  FIRST:: if( printf(""))
  printf("Face");
  else
  printf("Focus");
  If these is case then output should be Foucs, AND it is not given in the option.
  
  SECOND CASE: if( printf(" ")) //space inside printf statement
  printf("Face");
  else
  printf("Focus");
  In second case the output should be _Focus.... where _ represents space.
• 6 years agoHelpfull: Yes(3) No(5)
• In the above case some compilers shows warring and some shows output ....
  So the actual output is FOCUS .
• 6 years agoHelpfull: Yes(3) No(0)
• Actually the built-in function printf( ) returns the integer corresponding to number of characters it prints, now coming to your query
  
  printf(“”);
  Here printf returns 0 since, the count of characters it printed is 0.
  
  ‘’-0
  
  if(0) is false ( if (any positive integer ) is always true )so the body of “else” will be executed.
• 6 years agoHelpfull: Yes(2) No(0)
• (1) Error because case its 1, so true are not in the comment line it is written in next line
• 6 years agoHelpfull: Yes(0) No(1)
• if statement is true so the output will be true part""Focus
• 6 years agoHelpfull: Yes(0) No(1)
• if condition is false so it takes the false part
  the answer is 3
• 6 years agoHelpfull: Yes(0) No(0)
• printf returns number of characters that it prints
  
  out put should be Face
• 6 years agoHelpfull: Yes(0) No(2)
• since printf in if part is used to print the characters .
  if(printf("")) will be zero hence else part will be executed
  ans:focus
• 6 years agoHelpfull: Yes(0) No(0)
• Face.
  The if codtion works as true one.
• 5 years agoHelpfull: Yes(0) No(0)