3,7,13,23,41,??

• 75
  
  First difference 4, 6, 10, 18, 34, ....
  2nd difference 2, 4, 8, 16, 32, ....
  So next number is 41+34=75
• 6 years agoHelpfull: Yes(22) No(9)
• 2^1+1,2^2+3,2^3+5,2^4+7,2^5+9,2^6+11
  2+1,4+3,8+5,16+7,32+9,64+11
  3,7,13,23,41,75....
  Ans is 75
• 6 years agoHelpfull: Yes(10) No(0)
• ans=75
  3 to 7 difference=4
  13 to 7 difference=6
  23 to 13 differnece=10
  41 to 23 difference=18
• 6 years agoHelpfull: Yes(5) No(5)
• 61
  3&7 missing prime no.is 5 =1;
  7&13 missing prime no.s 11=1;
  13&23 m p n. 17,19 = 2;
  23&41 m.p.n. 29,31,37=3;
  41&61 m.p.n.43,47,53,59= 4
• 6 years agoHelpfull: Yes(2) No(2)
• answer is 57
• 6 years agoHelpfull: Yes(2) No(3)
• 3,7,13,23,41..??
  answer is 75
  difference between 7&3=4 | difference between 4&6=2
  13&7=6 |difference between 10&6=4
  23&13=10 |difference between 18&10=8
  41&23=18 |so the next will be equal to 2*8=16
  18+16=34(it is difference for last no's of the series)
  so this differnece added to given last no of the series i.e., 34+41=75
• 6 years agoHelpfull: Yes(2) No(1)
• Is this not a prime number series? I think 43 would be the next term.
• 6 years agoHelpfull: Yes(1) No(8)
• 3 7 13 23 41 ...
  First difference 4, 6, 10, 18, 34, ....
  2nd difference 2, 4, 8, 16, 32, ....
  So next number is 41(present no)+34( two differences)=75
• 6 years agoHelpfull: Yes(1) No(0)
• 75
  first, we find the difference that is 4,6,10,18,34,...
  and 2nd is 2,4,8,16,34
  after that 41+34=75
• 6 years agoHelpfull: Yes(1) No(1)
• 75
  2 stage difference
• 6 years agoHelpfull: Yes(1) No(1)
• 3,7,13,23,41,?? 7-3=4 13-7=6, 23-13=10, 41-23=18
  i.e 4,6,10,18 (Difference is increasing like 2,4,6 so next difference will be 8 )
  i.e. 18+8+26 Hence Answer will be 41+26=67.
• 6 years agoHelpfull: Yes(1) No(1)
• 2*1+1=3
  2*2+3=7
  2*4+5=13
  2*8+7=23
  2*16+9=41
  2*32+11=75
  
  ans=75
• 6 years agoHelpfull: Yes(1) No(0)
• ans is 75,
  +2 +4 +8 +16
  +4 +6 +10 +18 +34
  3, 7, 13, 23, 41, ??
• 6 years agoHelpfull: Yes(0) No(0)
• 75 because 41 +34 =75
• 6 years agoHelpfull: Yes(0) No(0)
• 59....The differnce is 4
• 6 years agoHelpfull: Yes(0) No(2)
• 3,7,13,23,41,..... => 7-3=4 , 13-7=6 i.e (4*2-2) , 23-13=10 i.e(6*2-2) , 41-23=18 i.e(10*2-2) Thus, difference of the two numbers is multiplied by 2 and then subtracted by 2. so 18*2-2=34. Hence, answer is 41+34=75
• 6 years agoHelpfull: Yes(0) No(0)
• 57
  16 difference there
• 6 years agoHelpfull: Yes(0) No(0)
• 75.as it's happening as 2^1+1,2^2+3,2^3+5 and so on
• 6 years agoHelpfull: Yes(0) No(1)
• 3 7 13 23 41
  4 6 10 18
  2 4 8
  
  next will be 16
  18+16=34;
  then 34+41=75
• 6 years agoHelpfull: Yes(0) No(0)
• 3+4=7
  7+6=13
  13+10=23
  23+18=41
  41+34=75
  
  
  6-4=2^1,
  10-6=4=2^2,
  18-10=8=2^3,
  34-18=16=2^4
• 6 years agoHelpfull: Yes(0) No(0)
• 75 [(3*2)+1, (7*2)-1, (13*2)-3, (23*2)-5, (41*2)-5]
• 6 years agoHelpfull: Yes(0) No(0)
• 69 ans
  difference between numbers
  then .....
• 6 years agoHelpfull: Yes(0) No(0)
• 69 is answer
• 6 years agoHelpfull: Yes(0) No(1)
• Given:
  
  The series: 7, 13,23,41,??
  
  To find:
  
  The missing term( the next number after 41)
  
  Solution:
  
  For finding the logic behind the series, we first check the difference between the numbers.
  
  Here, we get to see a pattern which can be written as-
  
  (First number*2)-1
  
  (Second number*2)-3
  
  (Third number*2)-5 and so on
  
  So, each number is first multiplied by 2( constant factor) and then subtracted by a number that gets incremented by 2( 1,3,5,7,9 and so on).
  
  So, here we get:
  
  (7*2)-1 = 13( second number)
  
  (13*2)-3= 23( third number)
  
  (23*2)-5 = 41( fourth number)
  
  
  
  So the next number( missing one) in the series would be:(41*2)-7 = 75
  
  The missing number in the series is 75.
• 4 years agoHelpfull: Yes(0) No(0)