Write a program to swap two numbers without using a temporary
variable.

• #include
  #include
  int main()
  {
  int x = 10, y = 5;
  printf("numbers are x=%d ,y=%d",x,y);
  // Code to swap 'x' and 'y'
  x = x + y; // x now becomes 15
  y = x - y; // y becomes 10
  x = x - y; // x becomes 5
  
  printf("After Swapping: x = %d, y = %d", x, y);
  
  return 0;
  }
• 6 years agoHelpfull: Yes(6) No(0)
• void main()
  {
  int a,b;
  scanf("%d%d",&a,&b);
  a=a+b;
  b=a-b;
  a=a-b;
  printf("%d %d",a,b);
  }
• 6 years agoHelpfull: Yes(2) No(0)
• #include
  int main()
  {
  int a=10, b=15;
  a=a+b-(b=a);
  printf("a=%d b=%d" ,a, b);
  return 0;
  }
• 6 years agoHelpfull: Yes(2) No(0)
• we can write like this
  a=a+b
  b=a-b
  c=a-b
  
  
  or u can change the given numbers into binary and u can use a logic
  A=A XOR B
  B=A XOR B
  A=A XOR B
• 6 years agoHelpfull: Yes(1) No(0)
• sry there was a change in first logic
  a=a+b
  b=a-b
  a=a-b
• 6 years agoHelpfull: Yes(1) No(0)
• method 1: Use XOR operation
  a=a^b
  b=a^b
  a=a^b
  method 2:
  a=a+b
  b=a-b
  a=a-b
• 6 years agoHelpfull: Yes(1) No(0)
• #include
  
  int main() {
  int x=10,y=15;
  printf("before swaping numbers a=%d, b=%d",x,y);
  x=x+y;
  y=x-y;
  x=x-y;
  printf("nafter swaping number is a=%d , b=%d",x,y);
  return 0;
  }
  
  output:-
  
  before swaping numbers a=10, b=15
  after swaping number is a=15 , b=10
• 6 years agoHelpfull: Yes(1) No(0)
• #include
  #include
  void
  main ()
  {
  
  int a, b;
  
  printf ("Enter a and b : ");
  
  scanf ("%d%d", &a, &b);
  
  
  a = a + b;
  
  b = a - b;
  
  a = a - b;
  
  
  printf ("nnAfter Swapping a = %d , b = %d", a, b);
  
  
  
  }
• 6 years agoHelpfull: Yes(0) No(0)
• a=a+b;b=a-b;a=a-b;
• 6 years agoHelpfull: Yes(0) No(0)
• use concept---
  int a=5,b=6;
  a=a+b;
  b=a-b;
  a=a-b;
• 6 years agoHelpfull: Yes(0) No(0)
• b=a+b;
  a=b-a;
  b=b-a;
• 6 years agoHelpfull: Yes(0) No(0)
• void main()
  {
  int a,b,t;
  a=5;
  b=6;
  swap(int a,int b)
  {
  t=a;
  a=b;
  b=t;
  }
• 6 years agoHelpfull: Yes(0) No(4)
• a = a+b
  b = a-b
  a = a-b
• 6 years agoHelpfull: Yes(0) No(0)
• without using the third variable
  > take the input and b.
  >put, a=a+b;
  >put,b=a-b;
  >put, a=a-b;
  .print a and b
• 6 years agoHelpfull: Yes(0) No(0)
• This question can be easily solved using boolean 'xor' operation
  //let a=2, b=3
  a= a^b; //a=1 (2 xor 3)
  b= a^b; //b=2 (1 xor 3)
  a= a^b; //a=3 (1 xor 2)
  //Hence swapped
• 6 years agoHelpfull: Yes(0) No(0)
• value1=40 , value2=30
  value1=(value1+value2)-value1
  value2=(value1+value2)-value2
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int x=12;
  int y=10;
  x=x*y;
  y=x/y;
  x=x/y;
  printf("After swaping:n x=%d y=%d",x,y);
  }
• 6 years agoHelpfull: Yes(0) No(0)
• a=a+b;
  b=a-b;
  a=a-b;
• 6 years agoHelpfull: Yes(0) No(0)
• a=a+b;
  b=a-b;
  a=a-b;
• 6 years agoHelpfull: Yes(0) No(0)
• int a,b,c;
  a= 5;
  b=10;
  
  a = a + b;
  b = a - b;
  a = a - b;
• 6 years agoHelpfull: Yes(0) No(0)
• Python :
  
  x,y = y,x
  print(x)
  print(y)
• 6 years agoHelpfull: Yes(0) No(0)
• //python implementation:
  a=3
  b=5
  print("before swapping a is "+ str(a) +" & b is " + str(b) )
  a,b=b,a
  print("after swapping a is "+ str(a) +" & b is " + str(b) )
• 6 years agoHelpfull: Yes(0) No(0)
• Let the numbers be x and y,
  x=x+y;
  y=x-y;
  x=x-y;
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int n1=3,n2=4;
  printf("after swape %d ,%d"n1,n2);
  n1=n1+n2;
  n2=n1-n2;
  n1=n1-n2;
  printf("after swape %d ,%d"n1,n2);
  return 0;
  }
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int a,b;
  scanf("%d%d",&a,&b);
  a=a+b;
  b=a-b;
  a=a-b;
  printf("%d%d",a,b);
  return 0;
  }
• 5 years agoHelpfull: Yes(0) No(0)