A, B, C can complete a work in 15 20 and 30 days respectively. they all work together for 2 days then A leaves the work. B and C work for somedays and B leaves 2 days before completion of the work. how many days are required to complete the whole work?

• A=15 days
  B=20 days
  C=30 days
  
  Take LCM to find total work= LCM(15,20,30)=60 WORK
  A's work in 1 day= 60/15=4
  similarly,
  B's=3
  C's=2
  total days to complete the work be= d days
  
  now , according to question,
  
  (4*2)+(3*(d-2))+2*d=60(total work)
  8+3d-6+2d=60
  5d=58
  d= 11 3/5 days
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