In how many ways the word "KEYBOARD" can be arranged such that the vowels always occupy the odd places.

• the other 5 letters can be placed anywhere (without restriction)on the remaining places. No of ways to arrange the remaining 5 letters=5!=120 ways. So total no of words = Answer to the problem = 4*6*120=2880 words.
• 5 years agoHelpfull: Yes(3) No(6)
• Ans: 2880
  vowels*-EOA
  others#- KYBRD
  *#*#*#*#
  3 vowels to be selected in 4 positions(odd)=4c3
  3 vowels can be placed in 3! ways.
  Remaining 5 consonants can be placed in 5! ways.
  So, 4c3*3!*5!=2880.
• 4 years agoHelpfull: Yes(0) No(0)