What is the value of x?

(1) |x + 2| = 2|x - 2|
(2) x > 2

• If we take mod value as positive
  x+2=2(x-2)
  => x+2=2x-4
  => x=6
  If we take mode value as negative then we will get x=2/3 which is less than 2; condition no. 2 is not satisfied,
  so x will be 6
• 6 years agoHelpfull: Yes(8) No(0)
• |x+2|=2|x-2|
  x+2= 2(x-2)
  from this equation we are getting x=6
  x+2=2{-(x-2)}
  from this equation we are getting x=2/3
  
  since x>2
  therefore x=6
• 6 years agoHelpfull: Yes(3) No(1)
• x would be 6
  LHS, 6+2=8
  RHS 2(6-2)=8
• 6 years agoHelpfull: Yes(2) No(0)
• x-2=2(x-2), Since x>2
  2x-x=6
  x=6
• 6 years agoHelpfull: Yes(1) No(0)
• 6+2=2(6-2) so ans is 6
• 6 years agoHelpfull: Yes(1) No(0)
• take mod value as positive, now
  +x+2=+2(x-2)
  => x+2=2x-4
  => x=6
  If we take mode value as negative then x=2
  So ans is 6
• 5 years agoHelpfull: Yes(1) No(0)
• x+2=2x-4
  x=6
• 5 years agoHelpfull: Yes(1) No(0)
• 6+2=8, 2(6-2)=8
• 6 years agoHelpfull: Yes(0) No(0)
• X+2= 2x-4
  X=6
• 6 years agoHelpfull: Yes(0) No(0)
• X=6 and x>2
  Bcz x+2= 2x-4
  2x-x=2+4
  x=6
  
  So |6+2|=|12-4|
  8=8
• 5 years agoHelpfull: Yes(0) No(1)
• We take modulus as +ve
  +(X+2)=+(2X-4)
  X=6
• 5 years agoHelpfull: Yes(0) No(0)
• 5
  x+2=2x-4 solving it we get x=5
• 5 years agoHelpfull: Yes(0) No(1)
• By taking square on both sides
  x+2=4(x-2)
  x+2=4x-8
  10=3x
  x=3 (appx) and according to give condition x>2
  We cannot ignore bar on both sides like rest of you did
• 5 years agoHelpfull: Yes(0) No(0)