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. A sum of Rs.3000 is distributed amongst A, B and C .A get s 2/3 of what B and c got together and C gets 1/3 of what A and B got together. C‘s share is?
a.1200
b.2250
c.750
d.1050
Read Solution (Total 12)
-
- since A+B+C=3000 and A=2/3(B+c) and C=1/3(A+B)
so, from last equation 3C=A+B
so put in A+B+C=3000
3C+C=3000
4C=3000 so C=3000/4=750 - 6 years agoHelpfull: Yes(15) No(0)
- let their shares be a,b,c resp.
we know that-
a+b+c=3000
also,
a=2/3(b+c) and
c=1/3(a+b)
solving above 3 equations we will get value of c=750. - 6 years agoHelpfull: Yes(2) No(2)
- 750.
Take 3 variables. a+b+c=3000, a=2/3(b+c) and c=1/3(a+b). - 6 years agoHelpfull: Yes(1) No(0)
- answer 'C'
- 6 years agoHelpfull: Yes(1) No(2)
- A+B+C=3000
3A=B+C
3C=A+B
SO 4C=3000
THEN C=750 - 5 years agoHelpfull: Yes(1) No(0)
- A+B+C=3000
Now, take equations according to the statements
A=2/3(B+C)
C=1/3(A+B)
3C=A+B
Since A+B+C=3000, So A+B=3000-C
3C=3000-C
C=750 - 6 years agoHelpfull: Yes(0) No(0)
- 750 is the ans
- 6 years agoHelpfull: Yes(0) No(0)
- By doing some calculations I got c'share is 750i.e,option c
- 6 years agoHelpfull: Yes(0) No(0)
- OPTION C.750
- 6 years agoHelpfull: Yes(0) No(0)
- Ans. 750
If
C=1/3(a+b)
Then
If c =750
Then a+b=3c
=2250
Given a+b+c=3000
And 2250+750 =3000 - 6 years agoHelpfull: Yes(0) No(0)
- Answer is C.750
- 6 years agoHelpfull: Yes(0) No(0)
- A=1200
B=1050
c=750 - 6 years agoHelpfull: Yes(0) No(0)
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