what is the probability of getting all the 5 rejected items or all the 5 accurate items from a supplier if the probability of rejection of an item is 0.92

• p(r)=0.92
  p(a)=1-0.92
  = 0.08
  probability of 5 rejection items =0.92*0.92*0.92*0.92*0.92+0.08*0.08*0.08*0.08*0.08
  = 0.65
• 6 years agoHelpfull: Yes(4) No(1)
• probability of rejecting one item = 0.92
  probability of rejecting five item = (0.92)^5
  probability of one accurate item = 1- 0.92= 0.08
  probability of 5 accurate item = (0.08)^5
• 6 years agoHelpfull: Yes(2) No(5)
• Assuming every item is independent to each other, then the probability of the five of them being rejected is (0.92)*(0.92)*(0.92)*(0.92)*(0.92) = (0.92)^5 = 0.659.
  
  Since the probability of rejection is 0.92, the probability of acceptance/accuracy is 1–0.92 = 0.08. (Because it’s the opposite event), so the probability of getting all five of them accurate is (0.08)^5 = 0.000328
• 6 years agoHelpfull: Yes(1) No(0)
• Assuming every item is independent to each other, then the probability of the five of them being rejected is (0.92)*(0.92)*(0.92)*(0.92)*(0.92) = (0.92)^5 = 0.659.
  
  Since the probability of rejection is 0.92, the probability of acceptance/accuracy is 1–0.92 = 0.08. (Because it’s the opposite event), so the probability of getting all five of them accurate is (0.08)^5 = 0.000328
• 5 years agoHelpfull: Yes(1) No(0)