A says, ―If you reverse my own age, the figures represent my Brother‘s age. He is, of
course, senior to me and the difference between our ages is one-eleventh of their
sum.‖ Then A‘s brother‘s age is ?
A) 45
B) 54
C) 25
D) 52
E) None

• B) 54
  
  Let A's age=10x+y, then his brother's age=10y+x
  Given, difference of their age = (1/11)*Sum of their ages
  => (10y+x) - (10x+y) = (1/11)*(10y+x) - (10x+y)
  => 5x = 4y
  Above condition satisfies for x=4, y=5
  Hence A's age=45 and his brother's age=54
• 6 years agoHelpfull: Yes(0) No(0)
• Ans:45
  45 is reversed the answer become 54.54 is greater than 45.sum of their ages is 99.difference is 9.so 9 is 11 times of 99.so all the conditions satisfied.so answer is 45
• 6 years agoHelpfull: Yes(0) No(0)