B2CD, _____, BCD4, B5CD, BC6D

A. B2C2D
B. BC3D
C. B2C3D
D. BCD7

• Since every time number is shifting to right side, it gets increased by one
  BC3D
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• The numbers will be replacing as well as number is increasing by 1.so the answer will be BC3D
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• Every alphabet is increased by one from number 2 on each time
  BC3D
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• BC3D number is increasing and changing to next position
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• BC3D
  The location of the digit forms a cycle of 3.
  B2CD , 2 is in second place similar all.
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• Every time the number is increased by 1. The solution is BC3D
  option B
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• B is fixed in every part.. So we only change the author three letters. So my answer BC3D
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• 1st letter B is common so no need to look it.
  Observe that there is a series of no 2,_,4,5,6 in the above series. Therefore the missing no is 3.
  Besides this the no is changing its position in consecutive places and also in round like 2CD, _ , CD4, 5CD, C6D, therefore the missing one here is C3D. Answer is (B) BC3D.
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• every number is shifting to right side,increases by one,so the answer is B.BC3D
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• BC3D
  each time number is increasing an move to next position, except first position
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• BC3D
  By positions of alpahabets and numbers
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• BC3D because the value is shifting by incrementing one.
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• BC3D
  I think the numbers position starts after B and the sequence is B2CD,BC3D,BCD4,B5CD,BC6D,BCD7.............
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• B
  Alternatly number is changed along with alphabet
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• D
  every time it shift right side by one.. that's why it would be BC3D
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• BC3D
  Each number and the position of the number is incremented by 1.
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• correct ans is BC3D
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• Ans will be (B)
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• BC3D
  coz B2CD ----------,BCD4,B5CD
  Numerical is chaging its position by one and incremented by one every time
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• A) BC3D
  as the series is BnCD,BCn+1D,BCDn+2,Bn+3CD,BCn+4D and so on
  n=2 here
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• BC3D
  BECAUSE first-word second letter is a number. In the third word, a fourth letter is a number .In the second word ,third letter will be number.number in sequence order 2,3,4,5,6
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• B.BC3D AS THERE IS A CYCLE OF NUMBER
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• BC3D is the ans
  
  as we can see the digit term is linearly increasing, and observing the pattern to place the digit term we can say that first word have digit between 1st and 2nd letter, second word "hopefully" have it between 2rd and 3th character, next word have it after 3rd character,, and next word again have it between 1st and second character and so on...
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• BC3D add up the numbers they are in series
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• ans is B-BC3D because the no is skipped 1 place
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• BC3D
  the B gets the value 2 at first, then at third term third letter D gets 4 so the second term second letter should be getting a middle value to both of these so BC3D
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• Answer B.because every digit is incremented by one
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• OPTION B.BC3D
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• BC3D
  since every number is increasing to right side by 1
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• Every time the digit is shifted to right by one position.So the answer is BC3D
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• These are in order i.e BCD so first keep 2 3 4 5 6
  :B2CD,BC3D,BCD4,B5CD,BC6D
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