A two digit number is 1/3 rd of itself.consider unit digit is 'a' and tens digit is 'b'.How many two digits is possible?

• the question is actually if the two digits of a 2 digit no are multiplied and product is 1/3rd of the actual no. then find the no of such no?
  answer is 2
  15 and 24 are the only two no which satisfy the given condition
• 5 years agoHelpfull: Yes(11) No(4)
• wrong question!!!!
  how can a number be 1/3rd of itself
• 5 years agoHelpfull: Yes(6) No(0)
• do not ask incomplete questions
• 5 years agoHelpfull: Yes(3) No(0)
• question is incomplete or wrong
• 5 years agoHelpfull: Yes(1) No(0)
• The above question is wrong !
  May be the question look like this
  In a two-digit number the tens’ digit is 1 more than the units’ digit. The number itself is 6 times the sum of the digits. Find the number.
  A number with two digits can be written as AB where the A and the B are the digits in the tens and ones places. I set up one of the other questions you asked, I'll solve this one out in case you need to see how it's done.
  
  A = B + 1
  
  AB can be rewritten as 10A + B
  
  10A + B = 6(A + B)
  
  This gives me a system of equations. Since the first equation gives me A in terms of B, I'll replace the As in the second equation with B + 1. The first equation is saying that "A is the same thing as B + 1".
  
  So dealing with the second equation:
  
  10A + B = 6(A + B)
  
  10(B + 1) + B = 6(B + 1 + B)
  
  10B + 10 + B = 6B + 6 + 6B
  
  11B + 10 = 12B + 6
  
  B = 4
  
  Then A is one more than this, so A = 5.
  
  The number is 54.
• 5 years agoHelpfull: Yes(0) No(3)