Pipe A and pipe B could fill the tank in 15 hours. One day both pipes were opened for 5 hours then pipe B was closed. Pipe A filled the remaining amount in 30 hours. How many hours would it take to fill the tank using only pipe A?

• A and B can fill in 15 hours so they both are filling 6.67% every hour.
  after running for 5 hours a day 5*(6.67%)=33.35% if filled.
  remaining 66.65% is filled by A in 30 hours.
  so to fill 1 % of tank how much time will be required???
  (30/66.65)*100 to full the tank that would be 45 minute.
• 6 years agoHelpfull: Yes(0) No(0)
• 45 hours
  
  5 hours filling by A & B = 5*1/15=1/3
  Part of the tank remaining=1 - 1/3 = 2/3
  If pipe A alone can fill the tank in 'x' hours, then 30*(1/x)=2/3 => x=45
• 6 years agoHelpfull: Yes(0) No(0)