(1^3+2^3+3^3+.........+10^3)^10
Find Its Unit Digit
a) 2
b) 8
c) 5
d) 0

• c) 5
  
  Unit digits of 1^3, 2^3, 3^3, .........,10^3 are 1, 8, 7, 4, 5, 6, 3, 2, 9, 0 respectively.
  Adding them we get 5 at unit place.
  Now 5^n results into 5 at unit place.
  Hence number xxx5^10 will have 5 at its unit place.
• 6 years agoHelpfull: Yes(1) No(0)