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If a % of (a+b) + b % of (b+a)=(square(a)+square(b)) % of 1+ab % of x then find x(assume that ab!=0)
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- a*(a+b)+b*(b+a)=(a^2+b^2)*1+ab*x
a^2+ab+b^2+ab=a^2+b^2+ab*x
a^2+b^2+2ab=a^2+b^2+ab*x
2ab=ab*x
ab(2-x)=0
x=2 Ans - 6 years agoHelpfull: Yes(1) No(0)
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