Anuj and Amit started running on a circular trace of 400m with a speed of 5km/hr and 8 km/hr from the same point in same direction.. Find the time after which they will meet at starting point.

• first convert speed into m/s i.e for Anuj =5*(5/18)=25/18 m/s
  Amit=8*(5/18)=40/18 m/s
  To get the time at which they will meet at starting point is = LCM (T1,T2)
  T1is the time to cover 400m by anuj= 400*18/25=288 sec
  T2 is the time to cover 400m by Amit=400*18/40=180 sec
  
  Now lcm of T1,T2 =1440 sec=24 minute
• 6 years agoHelpfull: Yes(26) No(0)
• distance- 400m
  400m= 4/10km
  anuj= 4/10*5=4/50km/hr
  amit=4/10*8=1/20km/hr
  then l.cm(4/50,1/20)=l.cm(4,1)/h.c.f(50,20)= 4/10 ans
• 6 years agoHelpfull: Yes(1) No(5)
• time=dist/speed
  400*18/5%3
  480
• 6 years agoHelpfull: Yes(0) No(5)
• distance- 400m
  400m= 4/10km
  anuj= 4/10*5=4/50km/hr
  amit=4/10*8=1/20km/hr
  then l.cm(4/50,1/20)=l.cm(4,1)/h.c.f(50,20)= 4/10 ans
• 6 years agoHelpfull: Yes(0) No(2)
• time=0.4/(8-5)
• 6 years agoHelpfull: Yes(0) No(2)
• TIME=DISTANCE/SPEED
  =DISTANCE/RELATIVE SPEED
  =400%(5*5/18-8*5/18)
  =240MIN (INTO SECONDS)
  = 8 SEC
• 6 years agoHelpfull: Yes(0) No(2)