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Maths Puzzle
Numerical Ability
LCM and HCF
Find the least number which when divided by 5, 7 and 13 leaves the same remainder 3 in each case.
Read Solution (Total 4)
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- 458
LCM (5, 7, 13) = 455
So the required number=455+3=458 - 5 years agoHelpfull: Yes(5) No(0)
- lcm(5,7,13)=455
455+3=458 - 5 years agoHelpfull: Yes(1) No(0)
- 458
LCM (5,7, 13)=455+3=458 - 5 years agoHelpfull: Yes(1) No(0)
- In this case,
Take L.C.M. of 5,7,13=455
Required number=455+3=458 - 5 years agoHelpfull: Yes(1) No(0)
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