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The value of a machine depreciates from Rs 32,768 to Rs 21,952 in three years. What is the rate % of depreciation?
Read Solution (Total 4)
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- value of machine after n years=Initial Value(1-R/100)^n
21952=32768(1-R/100)^3
28=32(1-R/100)^3
R=12.5% - 6 years agoHelpfull: Yes(5) No(0)
- 32768:21952=512:343
now take cube root on both sides
8:7
so the rate is 1/8*100=12.5% - 6 years agoHelpfull: Yes(3) No(6)
- 21952=3276*(1+R/100)^3
R=33% - 6 years agoHelpfull: Yes(0) No(4)
- Let's R be the rate of depreciation
=>21,952=32,768[1-R/100]^3
=>R=12.5% - 6 years agoHelpfull: Yes(0) No(0)
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