The value of a machine depreciates from Rs 32,768 to Rs 21,952 in three years. What is the rate % of depreciation?

• value of machine after n years=Initial Value(1-R/100)^n
  21952=32768(1-R/100)^3
  28=32(1-R/100)^3
  R=12.5%
• 5 years agoHelpfull: Yes(5) No(0)
• 32768:21952=512:343
  
  now take cube root on both sides
  
  8:7
  so the rate is 1/8*100=12.5%
• 5 years agoHelpfull: Yes(3) No(6)
• 21952=3276*(1+R/100)^3
  R=33%
• 5 years agoHelpfull: Yes(0) No(4)
• Let's R be the rate of depreciation
  =>21,952=32,768[1-R/100]^3
  =>R=12.5%
• 5 years agoHelpfull: Yes(0) No(0)