When ‘M’ is divided by 6 it leaves a remainder 2 and when ‘N’ is divided by 6 it leaves a remainder 3. What will be remainder if ‘M-N’ is divided by 6 ? (M>N)

• M = 6m + 2 and N = 6n + 3
  so, M-N = 6(m-n) -1 = 6(m-n-1) + 5
  so the reminder is 5
• 5 years agoHelpfull: Yes(8) No(3)
• step-1
  m/6=2 and n/6=3
  step-2
  m/6-2=n/6-3
  step-3
  m/6-n/6=2+3
  step-4
  m-n/6=5
  we get m-n=6*5
  m-n=30
  when we divide m-n by 6
  we get 5
• 5 years agoHelpfull: Yes(5) No(2)
• Given M>N
  Let M=14 (M/6 with rem=2)
  N=9 (N/6 with rem=3)
  M - N = 14 - 9 = 5
  Therefore, 5/6 gives rem =5
• 5 years agoHelpfull: Yes(2) No(0)
• Division Algorithm:
  Dividend=(Divisor*Quotient)+Reminder
  M=6*m+2
  N=6*n+3
  Find M-N ?
  M-N=6m+2-(6n+3)
  =6m+2-6n-3
  =6(m-n)-1
  =6(m-n-1)-1+6
  =6(m-n-1)+5
  therefore, the reminder is 5
• 4 years agoHelpfull: Yes(1) No(1)
• M/6+2=N/6+3
  M/6-N/6=3-2
  M-N/6=1
  M-N=6
• 5 years agoHelpfull: Yes(0) No(15)
• given that m/6 remainder 2 and n/6 remainder 3 (m-n)/6 remainder is 5,
  since let m=26, n=21 so m-n=5
  now "5mod6" is 5
• 5 years agoHelpfull: Yes(0) No(1)
• The answer is 5
• 3 years agoHelpfull: Yes(0) No(0)