A boat travels 300m upstream in 15 mins its speed downstream is 8 5 time its upstream which of the

This question won't even need the distance and time.
If speed of boat =x and speed of current=y then
(x+y)=8/5(x-y)
=>y+8y/5=8x/5-x
=>13y/5=3x/5
=>y=13x/3

So b is the correct ans
5 years agoHelpfull: Yes(6) No(0)
Upstream speed = 300/15 = 20m/min
Downstream speed = 8/ 5 ×20 = 32m/min
Boat speed= (32+20)/2=26
Stream speed = (32-20)/2=6
5 years agoHelpfull: Yes(3) No(0)
In 15 mins boat travels 300 mtr
So, in 60 mins=(300*4)=1200mtr
So, (u-v)=1200
Thus we get (u+v)=1920
Sloving this two equation we get u=1560 and v=360
Now (v:u)=360:1560=3:13
5 years agoHelpfull: Yes(1) No(0)
time taken for going upstream= (distance travelled/ Speed of boat(B)-Speed of Stream(S))
300/(B-S)=15
B-S= 300/15= 20------------(1)
According to the condition:
B+S=8/5(B-S)
B+S=32---------------------------(2)
taking the two equation we get:
B=26 and S=6
S/B=6/26=3/13
S=3/13(B)
5 years agoHelpfull: Yes(1) No(2)
B is the rht answer
5 years agoHelpfull: Yes(0) No(2)
let us assume upstream=x-y
downstream=x+y
300/(x-y)=15
x-y=20
x+y=(8/5)(x-y)
3x-13y=0--->3x=13y--->y/x=3/13
speed of the current=y/x=3/13
5 years agoHelpfull: Yes(0) No(0)
Answer is b
5 years agoHelpfull: Yes(0) No(0)
b. speed of current=3/13 of speed of boat
s+v/s-v = 8/5
s-v = 300/15 = 20 m/min
so, s+v=32 m/min
s=6/26=3/13 v
3 years agoHelpfull: Yes(0) No(0)

A boat travels 300m upstream in 15 mins. its speed downstream is 8/5 time its upstream . which of the following option is correct?

a.speed of current=12/10 of speed of boat
b.speed of current=3/13 of speed of boat
c.speed of current=9/13 of speed of boat