Tickets are numbered from 1, 2....1100 and one card is drawn randomly what
is the probability of having 2 as a digit?
a ) 290/1100 b) 291/1100 c) 292/1100 d) 390/1100

• Answer: c
  Explanation:
  Numbers which dont have 2 from 1 to 9 = 8
  Numbers which don't have 2 from 10 to 99:
  Let us take two places _ _. Now left most place is fixed in 8 ways. Units place is filled with 9 ways. Total 72 numbers.
  Numbers which don't have 2 from 100 to 999 =_ _ _ = 8 × 9 × 9 = 648
  Numbers which don't have 2 from 1000 to 1099 =10_ _ = 9 × 9 = 81
  Finally 1100 does not have 2. So 1.
  Total number with no 2 in them = 8 + 72 + 648 + 81 + 1= 810
  Tickets with 2 in them = 1100 - 810 = 290
  Required probability = 290 / 1100
• 5 years agoHelpfull: Yes(7) No(5)
• Answer: A
  2 digit number from 200 to 299 is 100
  1 to 100 the 2 digit number is 19
  so 1 t0 199 and 300 to 110 = 19*10=190
  200 to 299 =100
  so 190+100=290
  probability =290/1100
• 5 years agoHelpfull: Yes(5) No(5)
• 290/1100 is the ans
• 5 years agoHelpfull: Yes(2) No(1)
• 290/1100 is the ans
• 5 years agoHelpfull: Yes(1) No(1)
• N(s) =1100
  N(e)=19*10+100=290
  P=290/1100
• 4 years agoHelpfull: Yes(1) No(0)
• Ans is 290/1100
• 5 years agoHelpfull: Yes(0) No(1)
• 291/1100 is the answer
• 3 years agoHelpfull: Yes(0) No(0)