Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

• let, slower horse takes X hrs.
  and faster horse takes X-5/6 hrs.
  faster horse reaches 5/6 or 50 min. before the slower horse.
  now, faster horse speed, S1
  and slower horse speed, S2
  as speed,= distance/time
  S1= 50/X-5/6.......(i)
  S2= 50/X........(ii)
  
  ATQ: 50/S1+S2=1
  50/(50/X-5/6)+(50/X)=1
  x=5/2 or x==1/3
  now, we will put the value 5/2 in equation (ii),
  S2=50/5/2=100/5=20
  so, slower horse speed is 20 kmph..ans
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