tcs
Exam
Numerical Ability
Number System
Let f(m,n) =45*m + 36*n, where m and n are integers (positive or negative) What is the minimum positive value for f(m,n) for all values of m,n (this may be achieved for various values of m and n)?
Read Solution (Total 7)
-
- f(m,n)=45(m)+36(n)
let m=1 and n=-1
f(1,-1)=45-36=9
So,9 is the minimum positive value. - 5 years agoHelpfull: Yes(3) No(0)
- m=1,n=-1
then 45(1)+36(-1)=45-36=9 - 5 years agoHelpfull: Yes(0) No(0)
- minimum positive value is 9
- 5 years agoHelpfull: Yes(0) No(0)
- 9 is the right answer becaus
- 4 years agoHelpfull: Yes(0) No(0)
- 9 is the right answer becaus
- 4 years agoHelpfull: Yes(0) No(0)
- for m, n take as 1,-1 then45*1+35*(-1)=9
the minimum possitive value. - 4 years agoHelpfull: Yes(0) No(0)
- answer is 9
- 4 years agoHelpfull: Yes(0) No(0)
tcs Other Question