15. In this question A^B means A raised to the power B. If f(x) = ax^4 - bx^2 + x + 5 and f(-3) = 2, then f(3) =
a. 1
b. -2
c. 3
d. 8

• Firstly we put the value x=-3 because given this f (-3)=2 so a*(-3)^4-b (-3)^2+(-3)+5
  81a-9b+(-3)+2=2
  
  
  81a-9b=0
  Again find the value of f (3)=?
  81a-9b+8 here we find 81a-9b=0 so and is 8
• 5 years agoHelpfull: Yes(3) No(2)
• answer is 8
  because when we substitute -3 in above equation ax^2 and bx^4 will be same even if x is negative or positive
  only the third term will change i.e.,we will be subtracting 3 .so by adding 3+3 to the answer 2 we can find out the value of f(3)=8.
• 5 years agoHelpfull: Yes(2) No(3)
• F(-3)=2 then
  Ax4+
  H
• 5 years agoHelpfull: Yes(0) No(0)
• 8 , just solve by putting value
• 4 years agoHelpfull: Yes(0) No(0)