IF X IS ADDED TO BOTH NUMENATOR AND DENOMINATOR IN FRACTION 2/3 AND 20/3,THEN FRACTION BECOME EQUAL.THE FACTOR OF X IS??

• (2+x)/(3+x) = (20+x)/(3+x)
  if we cross multiplied then we get
  x^2+5x+6 = x^2+23x+60
  5x+6=23x+60
  then 18x=(-54)
  the value of x is -3
• 5 years agoHelpfull: Yes(13) No(0)
• (2+x)/(3+x)=(20+x)/(3+x)
  6+5x+x^2=60+23x+x^2
  18x=-54
  x=-3
• 5 years agoHelpfull: Yes(2) No(1)
• i think it should be 0, because practically when you substitute 0 in both the fractions it will become equal but not with the other values
• 5 years agoHelpfull: Yes(2) No(2)
• x+2/x+3=20+x/3+x
  x^2+5x+6=23x+x^2+60
• 5 years agoHelpfull: Yes(1) No(4)
• (2+x)/(3+x)=(20+x)/(3+x)
  x^2+5X+6=x^2+23X+60
  x=3
• 5 years agoHelpfull: Yes(1) No(11)
• 1->(x+2)/(x+3)=(x+20)/(x+23)
  2-> cross multiply->(x+2)(x+23)=(x+3)(x+20)
  3->(x^+23x+2x+46)=(x^+3x+20x+60)
  4->25x+46=23x+60
  5->25x-23x=60-46
  6->2x=14
  7.Ans is 7.
• 5 years agoHelpfull: Yes(1) No(5)
• Question is wrong or mistyped.
• 4 years agoHelpfull: Yes(1) No(0)
• (2+x)/(3+x)=(20+x)/(3+x).
  then cross multiplication
  then x value is 37
• 5 years agoHelpfull: Yes(0) No(4)
• sorry... please ignore my last comment. By mistake i read the question wrong, i read 20/3 as 20/30.
• 5 years agoHelpfull: Yes(0) No(3)
• Answer is 3
• 4 years agoHelpfull: Yes(0) No(2)