4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4

• #include
  int main()
  {
  int n,i,j,k;
  printf("enter number nn");
  scanf("%d",&n);
  for(i=1;i
• 5 years agoHelpfull: Yes(7) No(21)
• #include
  void main()
  {
  int i,j,k,n;
  printf("enter n");
  scanf("%d",&n);
  for(i=1;i
• 5 years agoHelpfull: Yes(0) No(9)
• #include
  int main()
  {
  int n=4,a;
  a=n*2-1;
  for(int i=0;i
• 5 years agoHelpfull: Yes(0) No(2)
• Get the solution at:
  https://drive.google.com/file/d/16FkcQr9TM1IHx52uhHEOYdp6iIxzwIve/view?usp=drivesdk
• 4 years agoHelpfull: Yes(0) No(0)
• // Function to print the pattern
  void printPattern(int n)
  {
  int arraySize = n * 2 - 1;
  int result[arraySize][arraySize];
  
  // Fill the values
  for(int i = 0; i < arraySize; i++)
  {
  for(int j = 0; j < arraySize; j++)
  {
  if(abs(i - arraySize / 2) > abs(j - arraySize / 2))
  result[i][j] = abs(i - arraySize / 2) + 1;
  else
  result[i][j] = (abs(j-arraySize / 2) + 1);
  
  }
  }
  
  // Print the array
  for(int i = 0; i < arraySize; i++)
  {
  for(int j = 0; j < arraySize; j++)
  {
  cout
• 4 years agoHelpfull: Yes(0) No(0)