One gear pulley rotates at a speed of 3 rev/sec another gear
roates at 5 rev/sec.
if both start together after how many seconds will they be
together again?

• Simply 1 sec
  Bcoz both pulley completes its own revolutions and return to their inital state in a sec..for example
  let pulley A has point 'a' as starting point and pulley B has 'b' as starting point..
  let a one second revolution..
  1. 'a' and 'b' start together..its right..
  2. After one second again they must return after 3 rev and 5 rev respectively..[one complete revolution is represented by its returning to the starting point..
  So definitely 1second or every second is the right answer
• 6 years agoHelpfull: Yes(5) No(3)
• 3 rotates 3,6,9,12,15
  5 rotates 5,10,15
  because ans is 15
• 6 years agoHelpfull: Yes(4) No(6)
• its simply the LCM of both the numbers. similar to the case of two person running in the track with diff. speed,.
• 6 years agoHelpfull: Yes(0) No(0)
• 15
  lcm of both
• 6 years agoHelpfull: Yes(0) No(0)
• Its 15
  Because lcm of both is 15
• 6 years agoHelpfull: Yes(0) No(0)
• L.C.M of both ,which is 15 ans
• 6 years agoHelpfull: Yes(0) No(0)
• ans is 1. they have not given time .they have given frequency .so they will come at start position in 1 sec.
• 6 years agoHelpfull: Yes(0) No(0)
• lcm of 3 AND 5
• 6 years agoHelpfull: Yes(0) No(0)
• find the lcm of 3,5
  it is 15
• 6 years agoHelpfull: Yes(0) No(0)
• 5P3*6!/2! IS THE SOLUTION
• 5 years agoHelpfull: Yes(0) No(0)
• 3 rotates 3,6,9,12,15
  5 rotates 5,10,15
  because ans is 15
• 2 years agoHelpfull: Yes(0) No(0)