A new car is driven 878 miles in year 1. It is driven 1150 miles in year 2. In each of year 3, 4, and 5 the car is driven 4% more miles than in the previous year. How many total miles the car will be driven at end of year 5?

• Y1 = 878
  y2= 1150
  Y3 = y2+4% of y2
  1150+1150*4/100
  = 1196
  same way
  Y4 = 1243.84
  Y5 = 1293.59
  Total Miles = 5761.4
• 6 years agoHelpfull: Yes(12) No(1)
• 878 - 1st year
  1150 - 2nd year
  1150+46(4%1150)=1196 -3rd year
  1196+48 approx(4%1196)=1244 -4th year
  1244+50 approx(4%1244)=1296 -5th year
  the answer is 5762 miles
• 6 years agoHelpfull: Yes(4) No(0)
• =878+1150+1150*1.04+1150*1.04^2+1150*1.04^3 = 5761.4336
• 6 years agoHelpfull: Yes(2) No(0)
• X1 = 878
  X2= 1150
  X3 = X2+4% of X2
  1150+1150*4/100
  = 1196
  same way AS
  X4 = 1243.84
  X5 = 1293.59
  Total Miles Driven= 5761.4
• 6 years agoHelpfull: Yes(1) No(0)
• let 100 miles so 4% at each year for 3 years:
  100 + 4% of 100 = 104
  104 + 4%of 104 = 108.16
  108.16 + 4% of 108.16 = 112.4864
  
  for 100 miles ------------------------------ 112.4864
  for 1 mile--------------------------------------- 112.4864 / 100
  for 1150 miles---------------------------------- 112.4864*1150 / 100
  = 1293.6
• 6 years agoHelpfull: Yes(1) No(2)
• Y2+Y3+Y4+Y5= 1150(1.04^4-1)/(1.04-1)
• 6 years agoHelpfull: Yes(0) No(0)