If a^2 = b^3 = c^5 = d^6, then log(base)d (abc) =

1) 28/9
2) 31/5
3) 34/5
4) None of these
5) maaf kar bhai

• 31/5
  
  log(base)d a^2= log(base)d b^3= log(base)d c^5= log(base)d d^6
  log(base)d a^2= log(base)d b^3= log(base)d c^5=6
  =>log(base)d a^2=6 =>2log(base)d a=6 =>log(base)d a=3
  similarly log(base)d b=2, log(base)d c=6/5
  log(base)d (abc) = log(base)d a+log(base)d b+log(base)d c=3+2+6/5=31/5
  
• 11 years agoHelpfull: Yes(0) No(0)