MBA
Exam
the sum of the squares of the fifth and eleventh term of an AP is 3 and the product of the second and fourteenth term is equal to P. find the product of first and fifteenth term of the AP. plz tag me in the answer. 1) (58P-39)/45 2) (98P+39)/72 3) (116P-39)/90 4) (98P+39)/90
Read Solution (Total 1)
-
- Already solved in m4maths
(T5)^2+(T11)^2=3
T2*T14=P
T1*T15=?
(a+4d)^2+(a+10d)^2=3
2a^2+28ad+116d^2=3.....(1)
(a+d)(a+13d)=P
a^2+14ad+13d^2=P
a^2+14ad = P- 13d^2
1.5-45d^2=P
2P=3-90d^2...........(2)
a^2+14ad=?
=P-13d^2
=P-13(3-2P)/90
=(116P-39)/90
option (C) - 11 years agoHelpfull: Yes(0) No(0)
MBA Other Question