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LCM and HCF
A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?
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- To find the least number of cans we need to find the HCF of 368, 80 and 144 which is 16.
368 = 2*2*2*2*23,
80 = 2*2*2*2*5
144*2*2*2*2*3*3
HCF = 2*2*2*2 = 16
Now least number of cans required = (368+80+144)/16 = 23+5+9 = 37.
Ans = 37 cans required of 16 litres each. - 5 years agoHelpfull: Yes(1) No(0)
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