If I decrease my speed by 25% of original speed, I reach office 8 minute late. What is my usual time and new time (in minutes) of reaching office? [A] 22, 30 [B] 24, 32 [C] 20, 28 [D] 18, 26

• Correct Answer is Option [B]
  
  Let the speed be "x" & usual time taken be "t".
  
  Therefore, speed = (distance/time) => x=(d/t)
  By decreasing by 25%, 0.75x=(d/t+8)
  Since the distance is same, xt = 0.75x * (t+8) => t=24 min.
  New time of reaching the office is t+8 = 24+8 = 32mins.
• 5 years agoHelpfull: Yes(1) No(0)
• answer is B.
  V*t=(0.75*v) (t+8)
  solving this we get 24 and 32
• 5 years agoHelpfull: Yes(1) No(0)
• By going through the options...
  1)22,30
  25% of 30 =7.5
  (30-7.5)=22.5 not equal to 22.
  2)24,32
  25% of 32=8
  (32-8)=24 .. It is the decreased speed.
  finally it matches with the options. available
  
  Jst repeat the same prices for 3 nd 4 options.... The combination does not satisfy... Only 2nd option satisfies the principle mentioned in the question
• 5 years agoHelpfull: Yes(1) No(0)