GRE Exam Numerical Ability Percentage

An investor divides $12,000 into two investments, one paying 7% and one 8% annually. At the end of the year she has made $870. How much did she invest at 8%?

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Let the investment divided into 2 parts be "x" and "y" such that x + y = 12000
(7x/100) + (8y/100) = 870
7x + 8y = 87000
7x + 7y + y =87000
7(x+y) + y = 87000
7(12000) + y = 87000
y = $ 3000 => is invested at 8%.
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