In a triangle ABC, point D lies on BC such that AD = BD = CD. If angle BAD = 50°, what is angle BCA? A) 30° B) 40° C) 50° D) 60° E) 70°

• Correct Answer is Option (B)
  
  Since, AD=BD=CD, anglecABD = angle BAC = angle ACD
  In triangle ADB, since, angle BAD = 50, angle ABD = 50 degrees
  On computing the Angle-Side-Angle property of similar triangles we get angle ACD = angle DAC = 40 degrees.
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