2/3rd of the balls in a bag are blue, the rest are pink.
if 5/9th of the blue balls and 7/8th of the pink balls are
defective, find the total number of balls in the bag given
that the number of non defective balls is 146.

• let the total number of balls be x
  blue balls = 2/3*x rest remaining means 1-2/3 = 1/3x
  given condition 5/9th of blue and 7/8th of pink balls are defective
  i.e., 5/9 * 2/3x + 7/8* x/3= x-146 (given total number of non defectives = 146)
  (80x+63x)/216 = x-146
  143x/216 = x-146
  x- 143x/216 = 146 => 73x/216 = 146 => x/216 = 2
  x= 432
• 5 years agoHelpfull: Yes(19) No(2)
• let the total number of balls be x
  blue balls = 2/3*x rest remaing means 1-2/3 = 1/3x
  given condition 5/9th of blue and 7/8th of pink balls are defective
  i.e., 5/9 * 2/3x + 7/8* x/3=146 (given toatal number of defectives = 146)
  (80x+63x)/216 = 146
  143x = 31,536
  x = 220.53
• 6 years agoHelpfull: Yes(4) No(10)
• let the total no of ball= x
  no of blue balls= 2/3x
  rest no of balls i.e. pink= 1-2/3x= 1/3x
  condition is:-
  defective blue balls = 5/9
  defective pink balls = 7/8
  then the total balls=
  5/9*2/3x + 7/8*1/3x = 146
  0.37x + 0.29x = 146
  0.66x = 146
  x = 221.21 Ans
• 5 years agoHelpfull: Yes(2) No(0)
• let the total number of balls be x
  blue balls=2/3*x, pink ball=1-2/3=1/3x
  now from this question,
  non-defective ball(blue)=1-5/9=4/9,& pink=1/8
  equation,
  (2/3x*4/9)+(1/3x*1/8)=146
  x=490.56
• 5 years agoHelpfull: Yes(2) No(0)
• Let, Total number of balls in a bag = X.
  
  2/3*X = Blue balls
  1/3*X = Pinks balss
  
  5/9*2/3*X + 7/8*1/3 = 146
  
  On solving , X = 438.
• 6 years agoHelpfull: Yes(1) No(6)
• let x be the number of balls .
  blue balls: 2x/3
  red balls: 1x/3
  blue defected balls: (2x/3)*(5/9)
  blue non defective balls:(2x/3)*(4/9)
  red defected balls: (1x/3)*(7/8)
  red non defective balls: (2x/3)*(1/8)
  total non defective balls: (2x/3)*(4/9)+(1x/3)*(1/8)=146
  8x/27+x/24 =146
  64x/216+9x/216=146
  73x/216=146
  73x=146*216
  x=(146*216)/73
  x=432
  i.e the total number of balls is 432
• 4 years agoHelpfull: Yes(1) No(0)
• LCM of denominators(3, 9, 8)=3X9X8
  B--->(2/3)3X9X8--->2x9x8
  P---->(1/3)3X9X8--->9X8
  
  DB--->(5/9)X2X9X8-->5x2x8-->80
  DP--->(7/8)X9X8--->7x9-->63
  
  TD-->143
  T ND-->3X9X8-143-->216-143=73
  But T ND is 146
  
  so, (146/73)X3x9X8=216x2=432 Ans.
• 5 years agoHelpfull: Yes(0) No(1)
• Let the total numbers of the ball in a bag be x.
  
  Blue balls = 2/3 of x
  
  Pink ball = x - 2x/3
  
  = x/3
  
  Now,
  
  Defective Blue balls = 5/9 of (2/3 of x)
  
  = 5/9 × 2/3 × x
  
  = 10/27 × x
  
  Defective Pink balls = 7/8 of x/3
  
  = 7x/24
  
  Now, According to the Question, Defective Blue and Pink balls = 146
  
  10x/27 + 7x/24 = 146
  
  ⇒ (80x + 63x)/216 = 146
  
  ∴ 143x = 146 × 216
  
  ⇒ x = 220.53
  
  ≈ 221 balls.
  
  Hence, the total numbers of the ball in a a bag is 221 balls.
• 5 years agoHelpfull: Yes(0) No(2)
• 5/9 × 2/3 × x
  
  = 10/27 × x
  
  Defective Pink balls = 7/8 of x/3
  
  = 7x/24
  
  Now, According to the Question, Defective Blue and Pink balls = 146
  
  10x/27 + 7x/24 = 146
  
  ⇒ (80x + 63x)/216 = 146
  
  ∴ 143x = 146 × 216
  
  ⇒ x = 220.53
  
  ≈ 221 balls.
• 5 years agoHelpfull: Yes(0) No(1)