MBA Exam

xy + zy = 37 and xz + zy = 72. Find the number of ordered triplets (x, y and z) such that x, y and z are positive integers.

1) 1
2) 3
3) 2
4) 0

Read Solution (Total 1)

1

35,1,2
y(x+z)=37; y can be equal to 1 only.x+z=37
z*(x+y)=72
z(x+1)=72 ; only possible values x=35,z=2
11 years agoHelpfull: Yes(1) No(0)

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