The value of a machine depreciates from Rs 2000000 to Rs 1409938 in three years. What is the percentage rate of depreciation? A) 12% B) 12.5% C) 11% D) 10%

• final value=old value(1-(R/100))^n
  1409938=2000000(1-(R/100))^3
  1409938/2000000=(1-(R/100))^3
  (89/100)^3 =(1-(R/100))^3
  89/100=1-(R/100)
  89/100=(100-R)/100
  89=100-R
  R=11%
• 5 years agoHelpfull: Yes(2) No(0)
• =(2000000-1409938)/3
  =196687.3 per year
  rate%=196687.3/2000000
  =9.834365
  =10%
• 5 years agoHelpfull: Yes(0) No(3)