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Numerical Ability
Permutation and Combination
A student is to answer 10 out of 13 questions in an examination such that, he must choose at least 4 from the first 5 questions. The number of choices available to him is A)168 B)156 C)182 D)196
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- 4 from first 5 questions ...so 5 questions selected , remaining 8 questions
5C4 × 8C6+ 5C5× 8C5 = 196 - 5 years agoHelpfull: Yes(1) No(0)
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