A train running at 5/12 of its original speed reached a place in 18 hours. How much time (in hours) could be saved if the train would have run at its original speed? 1)7.5 2)10.5 3)15 4)18

• S1 x T1 = S2 x T2
  5/12 x 18 = 1 x T2
  T2 = 7.5
  time saved = 18 - 7.5 =10.5hrs
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• Ans 2) 10.5 hrs
  The train ran at less than its full speed, which means it ran at a fraction of its full speed. That fraction is 5/12, which translates into a decimal of 0.416
  These facts mean that at full speed the train would have reached its destination in less than 18 hours.
  Let t = time at full speed
  then t = 0.416 x 18hrs
  then t = 7.488hrs
  time saved = 18 hrs - 7.488 hrs = 10.5 hrs
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• s ?
  |------------------------------|
  5/12(s) 18 hrs
  
  s ~ 1/T
  
  s / 5/12(s) = 18 /?
  
  ?=7.5
  
  tym saved = 18.0 - 7.5 = 10.5
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• the answer to the question is 18
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