MBA
Exam
Numerical Ability
Number System
how many natural numbers are there with 24 factors where 2,3 and 5 are the only prime factors? 1) 36 2) 27 3) 12 4) 9
Read Solution (Total 2)
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- 24=2^3*3
These powers have to be distributed in 3 places…
A+b+c=3 has 10 soln
X+y+z=1 has 3 soln
Net =10*3=30 but here 2,2,6 is also included 3 times..hence ans =30-3=27
- 11 years agoHelpfull: Yes(1) No(2)
- number of factors =(m+1)*(n+1)*(c+1)
24=2*3*4
=2*2*6
with prime numbers as 2,3 and 5. using permutation and combination
2^1*3^2*5^3 can be arranged in 6 different ways
similarly, 2^3*3^1*5^2 can be arranged in 6 different ways
2^3*3^2*5^1 can be in 6 different ways.
and 2^2*3^3*5^1 can be in 6 different ways.
and similarly, 2*2*6 can be in 3 different ways.
so 6+6+6+6+3=27
- 8 years agoHelpfull: Yes(0) No(1)
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