25. The prime factorization of integer N is A x A x B x C, where A, B and C are all distinct prime integers. How many factors does N have?

• 12 because N=A*A*B*C;N=A^2*B*C=(2+1)(1+1)(1+1);=12
• 5 years agoHelpfull: Yes(22) No(7)
• 12
  This is because the number of factors is (a1+1)*(a2+1)*(a3+1)..... where a1 is the power of the first prime in the prime factorization of the number and so on
• 5 years agoHelpfull: Yes(1) No(0)
• All three statement are TRUE
• 5 years agoHelpfull: Yes(0) No(6)
• (2+1)(1+1)(1+1)
  =3*2*2=12
• 5 years agoHelpfull: Yes(0) No(0)
• We have a formula
  p1^a1.p2^a2,p3^a3..............pn^an=(a1+1)(a2+1)..........(an+1)
  therefor (2+2)(1+1)(1+1)=12
• 3 years agoHelpfull: Yes(0) No(0)