Java
Programming and Technical
Programming
Technical
Which checks the object code to determine whether there are more efficient means of execution?
1)Interpreter
2) Linker
3)Compiler
4) Optimizer
Read Solution (Total 15)
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- interpreter
- 5 years agoHelpfull: Yes(2) No(0)
- 4) Optimizer : it applies methods like Common sub expression elimination, Loop unrolling, Operator reduction, etc to improve code execution time.
- 5 years agoHelpfull: Yes(1) No(0)
- interpreter
- 5 years agoHelpfull: Yes(0) No(0)
- interpreter is the answer
- 5 years agoHelpfull: Yes(0) No(0)
- 1) Interpreter is the answer because it is used to execute line by line operation in a java byte code program
- 5 years agoHelpfull: Yes(0) No(0)
- Interpreter
- 5 years agoHelpfull: Yes(0) No(0)
- Compiler The code excution done by the object .class
- 5 years agoHelpfull: Yes(0) No(1)
- interpreter because it is used to execute line by line operation in a java byte program
- 5 years agoHelpfull: Yes(0) No(0)
- 1)Interpreter :line by line rechecked with the help of Interpreter.
- 5 years agoHelpfull: Yes(0) No(0)
- interpreter
- 5 years agoHelpfull: Yes(0) No(0)
- Interpreter
- 5 years agoHelpfull: Yes(0) No(0)
- Optimzer. An interpreter simply transates high-level language into low-level language, but an optimizer optimizes the intermediate code when converting into machine language.
- 4 years agoHelpfull: Yes(0) No(0)
- 4) Optimizer
- 4 years agoHelpfull: Yes(0) No(0)
- Compiler will go through all the code and
- 3 years agoHelpfull: Yes(0) No(0)
- Optimizer , as just the name says .
- 3 years agoHelpfull: Yes(0) No(0)
Java Other Question
Circles and Distances
Problem Description
Task is to calculate the straight line distance between the two objects moving in a circular path. They may move at different velocities. The distance has to be calculated after N seconds.
The figure and commentary below it, explains the problem in detail.
com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@491cde5b:image1.png
We have two point objects B and C at rest on a straight line at a distance r1 and r2 units from a point A. At time t=0 seconds, the objects start moving in a circular path with A at the center with velocity v1 and v2 degrees per second.
Given inputs v1, v2, r1 and r2, calculate the distance between the B and C after N seconds.
Distance should be printed up to an accuracy of 2 places after the decimal point. Use Rounding Half-up semantics.
Input Format
First line contains velocity of object B in degrees per second (v1)
Second line contains distance of object B from A (r1)
Third line contains velocity of object C in degrees per second (v2)
Fourth line contains distance of object C from A (r2)
Fifth line contains time in seconds after which the distance between B and C, is to be measured (N)
Output
The distance between B and C, N seconds after they are set in motion
Constraints
v1, v2, r1, r2 > 0 and all are integer values.
r2 > r1
0 < n <= 100
The objects move in anticlockwise direction
v1, v2 <=360
r2 <= 100
Explanation
Example 1
Input
90
5
270
10
1
Output
15.00
Explanation
After 1 second, the object at B would cover 90 degrees and the object at C would cover 270 degrees. Both the objects would be vertically opposite to each other and would lie in a straight line.
So the distance between them would be equal to the sum of their distance from the origin A=5+10= 15
Find the nearest perfect square of the given number.
Sample input:600
Sample output:576.
Sample input:47011
Sample output:47089