A road network covers some cities.city c can be reached only from the city a or city b.the distance from a to c is 65 km and that from B to C is 30 km. The shortest distance from a to b is 58 km. The shortest distance from city P to A is 420 km and the shortest distance from city P to B is 345 km. The shortest distance from city P to city C in km is

• Answer:
  
  The shortest distance from city P to C is 375 kms.
  
  Step-by-step explanation:
  
  As we can see there are only 4 routes from city P to C
  
  a) from P to A and then A to C
  
  So , distance in this route will be
  
  = 420 + 65
  
  = 485 kms
  
  b) From P to B and then B to C
  
  So , distance in this route will be
  
  = 345 + 30
  
  = 375 kms
  
  c) from P to A then A to B and then B to C
  
  So , distance in this route will be
  
  = 420 + 58 + 30
  
  = 508 kms
  
  d) From P to B then B to A and then A to C
  
  So , distance in this route will be
  
  = 345 + 58 + 65
  
  = 468 kms
  
  Hence we can see that the shortest distance from P to C is 375 kms via route b) i.e from P to B and then B to C.
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