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The numbers from 5 to 26 are written side-by-side as follows 567..2526. What is the remainder of dividing the resultant number by 9?

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5678910111213141516171819120212223242526
then 5+6+7+8+9+1+0+1+1+1+2+1+3+1+4+1+5+1+6+1+7+1+8+1+9+2+0+2+1+2+2+2+3+2+4+2+5+2+6=125
1+2+5=8
8%9=8
so 8 is the answer
4 years agoHelpfull: Yes(6) No(3)

total sum is 341
and its reminder is 8
4 years agoHelpfull: Yes(2) No(0)
sum of numbers from 5 to 26 = (sum of numbers from 1 to 26 )-(1+2+3+4)
= (26*27/2)-10
= 341
now 341%9 = 8
so the answer is 8.
4 years agoHelpfull: Yes(2) No(0)

TCS Other Question

Which of the following represents the largest 4 digit number which can be added to 7855 in order to make the derived number divisible by each of the following numbers 12,14,21,33 and 54? How many of the integers from 1 to 86 (inclusive) contain the digit 4 or have the digit sum divisible by 4?